The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below
=% m/m =mass of the solute/mass of the solution x100
let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100
grams of glucose is therefore =2/100 = y/400
by cross multiplication
100y = 800
divide both side by 100
y= 8.0 grams
Answer:
B
Explanation:
you're moving the decimal 8 spots to the left so it can only be B
Answer:
i think is c,my ans will not be 100%correct
D. They all contain carbon as an important part of their structure.