Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
It's A. segment A"B" is closer to segment C than segment A"B".
Step-by-step explanation:
Answer:
n < 27
Step-by-step explanation:
let the number be n