Answer:
The Least Common Denominator of 3/4, 4/5 and 2/3
Would be,
4 × 5 × 3 = 60
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>60</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>L.C.D</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u>,</u></em><em><u> </u></em><em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u>/</u></em><em><u>3</u></em>
In order to solve, set up a proportion: 22/126=x/100. Cross multiply: 2200=126x. Divide by 126 on both sides: 17.46%=x
Answer:
Read below
Step-by-step explanation:
If there are 12 marbles it could split up many different ways for it to be equal among every color. 4 of each for 3 colors or 3 of each for 4 colors. The list goes on you could even have 12 different colors.
The coordinates of the point where asymptotes are crossing (3, 1)
think it's right. i don't now(or remember) any other ways