It consists of one specie instead of many specie
Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Answer:
antibodies being produced to fight off a pathogen inside the body
Explanation:
Specific immune responses, also known as the adaptive immune system are ways the body fights against pathogens. The body is able to identify cells that are unique to it. When pathogens bearing an unknown identity enter the body, antibodies are released to attack the antigens on the surface of these pathogens.
The body usually develops this immunity after a previous attack by the pathogen. Lymphocytes known as the B and T cells are released by the immune system t engulf the pathogens.
Answer: True.
Explanation: I took the test on K12 and received an A.