Answer: 0.935
Explanation:
Let S = z-score that has a probability of 0.175 to the right.
In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:
P(z ≥ S) = 0.175 (1)
Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.
Nevertheless, we can use the following equation:
P(z ≤ S) + P(z ≥ S) = 1
⇔ P(z ≤ S) = 1 - P(z ≥ S) (2)
Now using equations (1) and (2):
P(z ≤ S) = 1 - P(z ≥ S)
P(z ≤ S) = 1 - 0.175
P(z ≤ S) = 0.825
Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),
P(z ≤ S) = 0.825
⇔ S = 0.935
Hence, the z-score of 0.935 has a probability 0.175 to the right.
The answer is 0.744 just do the math
Answer:
96
Step-by-step explanation:
Hey there!!
How do we solve this problem :
We will use the combinations formula to solve this :
c ( n , r ) where n = 11 and r = 2
c ( n , r ) = n ! / r ! ( n - r ) !
... 11 ! / 2 ! ( 11 - 2 ) !
... 11! / 2! × 9!
... 11! / 2 × 9!
... 11×10×9×8×7×6×5×4×3×2 / 2×9×8×7×6×5×4×3×2
... 11×10 / 2
... 11 × 5
... 55 combinations.
Hence, the required answer = 55 , option ( d )
Hope my answer helps!
