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Let 'n' be the number of side of a regular polygon each angle are equal and sum of each angle equal to (n-2)×180. ∴For a regular pentagon have five equal side, n=5
∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108°
Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio
Therefore ∠ABE : ∠CBE = 36: 72
∴ ∠GCB + ∠CBE = 108° +72°=180°
Answer:
Step-by-step explanation:
Let x be the number
- Write it out: -26x - 22 = x - 90
- Combine like terms: -27x + 68 = 0
- Subtract 68 from each side, so it now looks like this: -27x = -68
- Divide each side by -27 to cancel out the -27 next to x. It should now look like this:
I hope this helps!