Answer:
b=9,a=12
Step-by-step explanation:
I solved by substitution:
b = 3/4a ---> plug this into the other equation
a + b = 21 is now a + 3/4a = 21
Reduce: 7/4a = 21
a = 12
Now solve for b:
b=3/4a is now b=3/4(12)
b=9
Answer:
4x -5
Step-by-step explanation:
3+2 (2x - 4)
Distribute
3 + 2*2x - 2*4
3+4x - 8
Combine like terms
4x +3-8
4x -5
Hello : here is the graph
Labor is $3 per bulb, there is 100 lamps, so the labor cost would be 100 x 3 = $300.
The cost of one bulb is 6.95, the total cost of bulbs is 100 x 6.95 = $695
The total fr bulbs and labor is $695 + $300 = $995
The bulbs last 5 years so, for a 10 year period you would need to change the bulbs twice so total cost for 10 years would be 995 x 2 = $1990.
To find the cost per year, divide the total cost by the number of years:
1990 / 10 = 199 per year. Round to $200 per year.
The answer is B.