Omitted value: The price of children ticket was omitted in the question, so i used $8 to solve. You can input the correct value and solve the same way following the steps.
Answer: 100 adult tickets must be sold.
Step-by-step explanation:
step 1
let x represent Adults
AND y represent children
Since the theater seats 250 people we have that
x+y = 250..... equation 1
Also price for Adult ticket = $11
and price children ticket =$8
With total sales at $2,300, we have that
11x + 8y= 2300----- equation 2
Step 2
Making y subject in equation 1
' x+y = 250
y= 250-x
Putting y= 250- x in equation 2
11x + 8(250-x)= 2300
11x +2000-8x= 2300
11x -8x = 2300-2000
3x= 300
x 300/3
x= 100.
To find y
x+y = 250
100+y=250
y=250-100
y=150
Therefore 100 adult tickets and 150 children tickets must be sold to get a total sales of $2,300
A . 1/15 equals 0.66
b. 5/12 equals 0.4166
c. 1/3 equals 0.333
d. 5/12 equals 4.6 as a round number
8). 0.4 equals 4/10 equals 2/5
9) 7.32 equals 7 3/2
10) 0.2 equals 2/10 equals 1/5
Hope this helps:)
Answer:
a = 6
x^2 + 6x is equal to x(x+6)
b=2
Denominator and numerator of the first term are multiplied by x.
c=6
Second term is multiplied by (x-6)/(x-6)
d=2
Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term
e=6
In the same way as d is carried over from b, e is carried over from c.
f = 6
2x - x + 6 = x + 6
g = 1
We factor out the (x+6) from the numerator and denominator
Answer:
Finding the distance between two distinct points on a plane is the same as finding the hypotenuse of a right triangle. From this perspective, the distance formula states that the distance of two distinct points on a plane is equal to the square root of the sum of the square of the rise and run.
<em>I </em><em>can </em><em>not </em><em>Put </em><em>Out </em><em>The </em><em>Points </em><em>So </em><em>Im </em><em>sorry. </em>
Try this options:
a. total - 6 digits, '6' - 1 digit, then probability of rolling a '6' is 1/6;
b. total - 6 digits, '6' - 1 digit, then probability of rolling 1,2,3,4,5 is 5/6;
c. if probability of rolling a '6' is p and not rolling a '6' is q, then p+q=1;
d. if expected probability of one rolling a '6' is 1/6, then numbers of times of rolling a '6' during 120 times is 120/6=20 times.
