Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
Answer:
3
Step-by-step explanation:
Calculate the distance using the distance formula
d = 
with (x₁, y₁ ) = (- 9, 8) and (x₂, y₂ ) = (- 3, - 1)
d = 
= 
= 
= 
= 
= 
= 
×
= 3
4/20 is 0.20, which is equivalent to 20%.
Remember that 1.0=100%, 0.5=50%, 0.2=20%, 0.05=5%, and so on.
9x^2 + 4x^3
Hope this helped
Answer:
7
Step-by-step explanation:
V = base x height
base = 5 x 6
5 x 6 = 30
V = 210
H = V/Base
H = 210/30
210/30 = 7
H = 7
