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2 years ago

11

I need to resolve this

1 answer:

Inessa05 [86]2 years ago

8 0

I cant see the other half

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Each side of a rhombus is 20 cm long and one of its diagonals is 24 cm in length, find the area of this rhombus?

vodomira [7]

Answer:

AB = 20 CM

OA = 1

__ × 24 cm

2

= 12 cm

AOB = 90 °

OB² == AB² - OA ²

$( {20}^{2} ) - ( {12}^{2} ) \\ = 400 - 144 \\ = 256 \\$

$ob \: = \sqrt{256} = 16 \\ bd \: = 2 \times ob \\ = 2 \times 16 \\ = 32cm \: \\$

AREA OF ABCD IS

$\frac{1}{2 } \times ac \times bd \\ = \frac{1}{2} \times 24 \times 32 \\ 384cm$

$hope \: its \: helpful \: \: to \: you \:$

6 0

1 year ago

Read 2 more answers

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

so

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

so

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

<em>Find the values of y</em>

<em>First solution</em>

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

<em>Second solution</em>

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

<em>First solution </em>

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

If h=2f/m+1 , solve the equation for F. Plz SHOW WORK!!!!

MArishka [77]

H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)

7 0

2 years ago

Read 2 more answers

What is the degree of the equation?

Kisachek [45]

Answer:

Degree: x= -1, $\frac{8}{5}$

leading coefficient: 5

Step-by-step explanation:

hope this helps!!!

5 0

2 years ago

Aryana wants to invest $43,000. She has two options. Option A gives her 6% compounded quarterly. Option B gives her 6% simple in

solmaris [256]

Answer:

Option A earns higher interest($84115.58)

the difference in interest between the two option is $197.9

Step-by-step explanation:

In the problem we are going to apply both the simple interest formula and compound interest formula and compare which has the best/higher returns

Given data

Principal P= $43,000

Rate r= 6%= 0.06

time t= 3years

n= 4 (applicable for compound interest compounded quarterly)

solving for option A gives her 6% compounded quarterly

the compound interest formula is

$A= P(1+\frac{r}{n} )^n^t\\A= 43000(1+\frac{0.06}{4} )^{4} ^*^3$

$A=43000(1+0.015)^{12} \\A=43000(1.015)^{12} \\A=43000*1.1956\\A= 51411.58$

Interest is $A-P= 51411.58-43000= 8411.58$ =$8411.58

solving for option B which gives her 6% simple interest annually

the simple interest formula is

$A=P(1+r)^{t} \\A=43000(1+0.06)^3\\A=43000(1.06)^3\\A=43000*1.191\\A= 51213.68$

Interest is $A-P=51213.68-43000= 8213.68$ = $8213.68

calculating the diference in interest between the two options we have

$8411.58-8213.68= 197.9$ = $197.9

Option A earns higher interest

8 0

2 years ago