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2 years ago

If m(-12) =0 is the result of M(x) using the reminder theorem then what do -12 and 0 represent?

1 answer:

3 0

Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that

Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as

Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.

Now consider two polynomials of degree 2. In this case we seek a single value of x such that

Hope this helped, Hope I did not make it to complated

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Solve the following multiplication problems. a. 9kg. 3hg. 1cg× 9 b. 11dg. 4cg. × 12 c. 10g. 5 dg. ×6. 5g 3dg. 4cg. × 8

ratelena [41]

Are these measurements?

5 0

2 years ago

A rectangular yard is 20 feet by 15 feet. The yard Is covered with grass except for an 8.5 feet. Square flower garden. How much

stich3 [128]

Answer: $227.75\ ft^2$

Step-by-step explanation:

<h3> The complete exercise is: "A rectangular yard is 20 ft by 15 ft. The yard is cover with grass except for 8.5 feet square flower garden. How much grass is in the yard?"</h3><h3 />

The area of a rectangle can be calculated with the following formula:

$A=lw$

Where "l" is the lenght of the rectangle and "w" is the width.

Based on the data given in the exercise, you can identify tha the length and the width of the rectangular yard are:

$l=20\ ft\\\\w=15\ ft$

Then, you can substitute these values into the formula and then evaluate in order to find the area of the entire yard:

$A_y=(20\ ft)(15\ ft)=\\\\A_y=300\ ft^2$

The area of the flower garden which is an square, can be calculated with this formula:

$A=s^2$

Where "s" is the side length.

In this case you know that:

$s=8.5\ ft$

Then the area of the flower garden is:

$A_g=(8.5\ ft)^2\\\\A_g=72.25\ ft^2$

<em> </em>Since this is not covered with grass, you need to subtract both areas calculated above in order to find the surface covered with grass in the yard.

This is:

$A_g=300\ ft^2-72.25\ ft^2\\\\A_g=227.75\ ft^2$

4 0

2 years ago

What is the value of x?<br><br> 4<br><br> 4√2<br><br> 8<br><br> 8√2

vaieri [72.5K]

I believe its the last one 8v2

7 0

2 years ago

A shopkeeper fixed the marked price of his radio to make a profit of 30 percentage. allowing rs 30 as a discount then the profit

dusya [7]

Answer:

rs 200

Step-by-step explanation:

Let cost price = x

At 30% profit; marked price of radio is 30% of x = (100% + 30%) = 130%x

Discount = rs 3%

Profit made = 30

Hence,

Marked price - discount = cost price + 30

130%x - 30 = x + 30

1.3x - 30 = x + 30

1.3x - x = 30 + 30

0.3x = 60

Divide both sides by 0.3

0.3x / 0.3 = 60/ 0.3

x =

1.3x / 1.3 = 60 / 1.3

x = 200

Hence, cost price = rs 200

7 0

2 years ago

Urgent answer please <br> Ax+ay+xa+ya

marin [14]

Answer:

Possible derivation:

d/dx(a x + a y(x) + x a + y(x) a)

Rewrite the expression: a x + a y(x) + x a + y(x) a = 2 a x + 2 a y(x):

= d/dx(2 a x + 2 a y(x))

Differentiate the sum term by term and factor out constants:

= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))

The derivative of x is 1:

= 2 a (d/dx(y(x))) + 1 2 a

Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):

= 2 a + d/dx(x) y'(x) 2 a

The derivative of x is 1:

= 2 a + 1 2 a y'(x)

Simplify the expression:

= 2 a + 2 a y'(x)

Simplify the expression:

Answer: = 2 a

Step-by-step explanation:

8 0

2 years ago