What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
To split this trinomial into two binomials, let's try and find two numbers which add to 6 and multiply to 8. To do this, we can list all the factors of 8 and then choose which factors also add to 6.
Factors of 8: (1, 8), (2, 4)
1 + 8 = 9, meaning that 1 and 8 are not the factors we are looking for. However, 2 and 4 do add to 6. By combining these numbers which an x (so that we can produce the term at the front of the trinomial), we find the binomials:
and
The answer is x + 2 and x + 4.
Step-by-step explanation:
tvt67tvyy8vy8vt67vt7v6vt67yvtv
Answer:
. if ΔJKL is congruent to ΔTUV, which of the following can you NOT conclude as being true? ... equals, minus, 15 Complete the missing value in the solution to the equation. ... salary of 74$ per week plus a commission of 4% of sales. if they had 75$ in ...
Step-by-step explanation: