Answer:
1008
Step-by-step explanation:
geometric sequence:
a=16
r=32/16=2
Sum of GS:
s=a(1-r^n)/(1-r)
S(6)=16(1-2^6)/(1-2)
=1008
Answer:
A=1
B=2
c=1
Step-by-step explanation:
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
