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2 years ago

5p - 14 = 8 p + 4 find p

Physics

1 answer:

Digiron [165]2 years ago

6 0

Answer:

Explanation:

5p - 14 = 8p + 4

5p = 8p + 18 <-- Moving constants to one side; add the same number of +14 to both sides.

-3p = 18. <-- The same thing with the variable itself.

p = -6 <-- Divide both sides by negative 3.

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A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial

kolbaska11 [484]

Answer:

a) vertically up

Explanation:

A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial acceleration of the stone, as it leaves the surface of the road is,

a) vertically up

b) horizontally forward

c) horizontally backwards

d) zero

e) greater than zero but less than 45 degrees below the horizontal

A vertically upward since that is the direction of centripetal acceleration at that time. as the stone enters the circular path of the tire, it does so with a centripetal acceleration which is directed upward

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2 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 117m in 25s

Scilla [17]

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2 years ago

Which of the following is NOT a natural source of light?

mixas84 [53]

Answer:

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2 years ago

Read 2 more answers

An object is 70 um long and 47.66um wide. how long and wide is the object in km?

Ganezh [65]

Answer:

length = 7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

1km = 1*10^3 m

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

1 μm = 1*10^(-6 - 3)km

1 μm = 1*10^(-9)km

Now with this relationship we can transform our measures:

Length: 70 μm is 70 times 1*10^(-9)km, or:

L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

W = 46.66*1*10^(-9)km = 4.666*10^(-8) km

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2 years ago

Knowing the constant g what will the gravitational force between two masses be if the gravitational force between them is 36n an

charle [14.2K]

The gravitational force between two masses is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the two masses
r is the separation between the two masses

We see that the force is proportional to the inverse of the square of the distance: $F \sim \frac{1}{r^2}$
therefore, if the distance is tripled:
r'=3r
The force decreases by a factor 1/9:
$F \sim \frac{1}{(3r)^2}= \frac{1}{9} \frac{1}{r^2}$

Since the original force was 36 N, the new force will be
$F' = \frac{1}{9} (36 N)= 4 N$

6 0

2 years ago