The probability that both grab oranges would be = 
Step-by-step explanation:
Given,
A bowl contains,
Apples = a = 5
Oranges = o = 2
bananas = b = 2
Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9
Now, Christian and Aaron come home from school and randomly grab one fruit each.
The probability of first selecting orange would be = 
Now, the oranges left would be 2 - 1 = 1
and total fruits would be = 9 - 1 = 8
Hence, the probability of selecting second orange would be = 
Therefore, the probability that both grab oranges would be = 
(7/2,-7) ther I hope it help
The information from the first equation gives you the information needed for the second. To solve the first equation you must rearrange the equation to isolate X. In order to do that you can first move the 3 to the other side of the equation by subtracting it from both sides (5x + 3 - 3 = 4 - 3) and then simplify that to (5x = 4 - 3) and further to (5x = 1). Then to move the 5 you must divide both sides by 5 so you get (5x/5 = 1/5) which can be simplified to (x = 1/5)
From this you can use the X value and input it into the second equation
Y = -3(1/5) and then solve for Y.
Hope this helps!
Answer:
for the first picture: 2.16
Step-by-step explanation:
12% of 18 is 2.16:
-convert 12 % to a decimal so 0.12 times 18
also, 12 % percent is 0.12 as a decimal because you move the decimal 2 places to the left to get .12
- multiply 0.12 times 18 to get 2.16 as the answer
I hope this helped for the first pic!
