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2 years ago

I am so confused on functions! Please help!

1 answer:

4 0

Functions are basically another way of expressing a way to get y or x or anything (mostly used for graphs) You will see functions like f(x)= 23y-5 (that was made up). Basically the number in the parenthesis in front of the f is what you're finding. So the equation after the equal sign is how to find whatever is being found. So in this case, finding x can be pretty easy. By the way, when graphing this you have x as the run and y as the rise.

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Can anybody help me with this equation?? :/

Ganezh [65]

Answer:

Step-by-step explanation:

A full rotation takes 360°. From the picture, it would take 5 rotations to achieve such full degree rotation. Hence, each bit of rotation covers 360°÷5=72°

6 0

2 years ago

Read 2 more answers

In a swimming class, 2/5 of the participants are girls. there are 24 boys in the class. find the total number of participants in

jeyben [28]

30 because 2/5 are girls so 3/5 are boys and 24/3 +8 so 1/5=8 so 8*5 + 40 kids

Hope this helped

please give me a thank you

8 0

2 years ago

PLEASE HELP WITH BOTH WILL CROWN BRAINLIEST !!!!

Korvikt [17]

41) you have a 40 day period
two visits with +75 centimeter growth each
3 visits with +6 each
in total 2*75+3*6=150+18=168
divide this by 40 days to get the average: 168/40=4.2 centimeters per day or 1.65 inches/day

42)
7x total
3x20
2x15
1x13
1x16

if you order these into a list:
13,15,15,16,20,20,20

the median is the middle value, in this case 16$
the mode is the most common value: 20$ which exists 3 times

3 0

2 years ago

What is the remainder of 2,445 ÷ 8

Kryger [21]

Answer:

305 Remainder 5

6 0

2 years ago

Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.

Fofino [41]

Because they're not inverses, not exactly. $\sin x$ is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of $x$ such that $\sin x=0$ , for example.

The standard function $\sin^{-1}x$ has a domain of $-1\le x\le1$ and outputs values between $-\dfrac\pi2$ and $\dfrac\pi2$ . This means that its inverse, $\sin x$ , is indeed its inverse as long as $-\dfrac\pi2\le x\le\dfrac\pi2$ .

$\dfrac{3\pi}4$ is larger than $\dfrac\pi2$ and thus does not fall in the "invertible part" of the domain of $\sin x$ . We have

$\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}$

which is a value between -1 and 1, so that

$\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

If we wanted to recover $\dfrac{3\pi}4$ , we'd have to redefine $\sin^{-1}x$ or define a new inverse function that works on a different branch of the domain of $\sin x$ .

7 0

2 years ago