9514 1404 393
Answer:
(3) 12
Step-by-step explanation:
Let x represent the length of leg XY. Then the length of YZ is x/2 and the area of the right triangle is ...
A = 1/2bh
A = 1/2(x)(x/2) = x²/4
36 = x²/4 . . . . . use the given value for area
144 = x² . . . . . . multiply by 4
√144 = 12 = x . . . . . take the square root
The length of leg XY is 12 cm.
Given:
The graph of a function .
To find:
The interval where .
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So, for
.
Now,
For , the graph of h(x) is above the x-axis. So,
.
For , the graph of h(x) is below the x-axis. So,
.
For , the graph of h(x) is below the x-axis. So,
.
Only for the interval , we get
.
Therefore, the correct option is A.