https://www.google.com/search?safe=active&q=Elvira+made+the+trip+on+Tuesday+and+David+made+the+same+trip+on+Wednesday+Elvira
+traveled+at+14+mph.+David+traveled+at+21+mph,+so+his+time+was+3+hours+less+than+Elvira%27s+time.+How+far+did+they+travel?
1 answer:
Answer:Let x and (x-3) represent Elvira's and David's times respectively
D = r*t
Distances traveled are equal in this example***
14mph*x = 21mph(x-3)
solving for x
14x = 21x - 63
63 = 7x
x = 9hr, the time that Elvira traveled. David traveled 6hrs (9hr-3hr = 6hr)
CHECKING our Answer***
14mph*9hr = 126mi = 21mph*6hr = 126mi
Step-by-step explanation:
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They all only have 1 term.
The 3rd one
You can factor 3 out of each term in the numerator. And then divide it by the 3 in the denominator.
Answer:
5 hours
Step-by-step explanation:
if 10 hours cover 650 miles, 1 hour covers 65 miles. When you divide 325 by 65 you get 5 hours.
an easier way is, 650 ÷ 2 = 325 miles, likewise when 10 ÷ 2 = 5 hours
Slope=5. The change in y is +5and the change in x values is +1. 5/1=5
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