Answer:
The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Answer:
Total momentum, p = 21.24 kg-m/s
Explanation:
Given that,
Mass of first piece,
Mass of the second piece,
Speed of the first piece, (along x axis)
Speed of the second piece, (along y axis)
To find,
The total momentum of the two pieces.
Solve,
The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.
The net momentum is given by :
p = 21.24 kg-m/s
Therefore, the total momentum of the two pieces is 21.24 kg-m/s.
Answer:
<u>A:cool fluid sinks</u>
<u>B:warm fluid rises</u>
<u>C:convection current</u>
Explanation:
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Answer and explanation;
In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing length of a pendulum with a frequency of one beat per second as the unit of length.
In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.
In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.
In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).
In 1984 the Geneva Conference on Weights and Measures has defined the meter as the distance light travels, in a vacuum, in 1299792458⁄ seconds with time measured by a cesium-133 atomic clock which emits pulses of radiation at very rapid, regular intervals.
The momentum, p, of any object having mass m and the velocity v is
Let and be the masses of the large truck and the car respectively, and and V_S be the velocities of the large truck and the car respectively.
So, by using equation (i),
the momentum of the large truck
and the momentum of the small car .
If the large truck has the same momentum as a small car, then the condition is
The equation (ii) can be rearranged as
So, the first scenario:
So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.
The other scenario:
So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.