one type of wave used to transmit a signal is a ultraviolet wave. infrared wave. radio wave. x-ray wave.

2 answers:

6 0

Please be more specific because they all transmit signals but the most common one is the radio wave because it transmits cellphone , televition and radio signals

Korvikt [17]2 years ago

6 0

Answer:

Radio Waves

Explanation:

Radio waves are of longest wavelength and with smallest frequency

So here we can say that the wavelength range is very large and frequency range is less so here these waves are safe to use as these are not dangerous to us.

Since all electromagnetic waves consist of energy of different range depends on the frequency of the waves so in order to use them for communication purpose we have to use those waves which will have less energy so that these waves will remain useful for us.

So here correct answer for communication purpose will be

RADIO WAVE

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2 years ago

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b

Natasha_Volkova [10]

Answer:

Part a)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

Outside the outer cylinder we will again use Guass law

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.