6y^2-7y-3-2y^2+9y+7 (pretend that you're multiplying -1 to 2y^2-9y-7 which is why 9y and 7 are positive now).
Now you're able to simplify your problem, so...
6y^2-2y^2= 4y^2
-7y+9y= 2y
-3+7=4
4y^2+2y+4
Might want to check my math but that's how you do it.
Answer:
depends on what the price of the bicycle is and the discount percentage
Answer:
Step-by-step explanation:
Given
Phone R-Us= $16.95 + $0.05 per SMS
Awesome Wireless = $22.95 + $0.02 per SMS
Required
Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us
Represent the SMS with S
For Phone R-Us, we have:
For Awesome Wireless, we have:
For Awesome Wireless is greater or equal to Phone R-Us, we have:
Collect Like Terms
Solve for S
<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>
Answer:
Explanation:
Let the full batch be x
Here given:
3/4 cup of sugar required to make 1/3 batch of cookies
Build equation:
Solve:
The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...
... C = 2πr
... C = 2π·(10 m) = 20π m
The height as a function of angle (t) is found by substituting for x and y.
... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)
The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.
Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be
... (20π m)·(4 m) = 80π m²
The amount of paint required to cover both sides of the fence is
... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L
_____
You can work out the integral for area as a function of t. When you do, you will find it gives this same result.