Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:
Now the lowest 80% of the amount invested can be represented as follows:
The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:
Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Answer:/
I,,,,M SORRYI NEED POINTSSS
Step-by-step explanation:
Answer: He has enough
Step-by-step explanation:120-107.40=12.60
20 x 10 = 200
45 - 10 = 35 - 8 = 27
8 x 8 = 64
20 - 8 = 22
22 x 45 = 990
The area of the shape is 990 square feet.
Hope I could help!
Answer: You can use this to help you out:
Determine the term life insurance amount per thousand on a 20-year-old male for a 10-year policy given that the face value of the policy is $65,000 and the annual premium is $291.85.
a.
$0.00449
c.
$0.2227
b.
$4.49
d.
$222.72
First find how many thousands on the amount of the face value
You do that by dividing the amount of the face value by 1000
65,000÷1,000=65
So the term life insurance amount per thousand is
291.85÷65=4.49...answer
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