Answer:
x = -1, y = 2 and z = 1
Step-by-step explanation:
The given system of equations are :
2x - y + 3z= -1 ....(1)
x + 2y - 4z = -1 ......(2)
y – 2z = 0 .....(3)
Equation (3) can be written as :
y = 2z
Use y = 2z in equation (2)
x + 2(2z) - 4z = -1
x + 4z - 4z = -1
x = -1
Put the value of x in equation (1) :
-2 -y +3z = -1
-y+3z = 1 ....(4)
Adding equation (3) and (4)
y-2z+(-y+3z)=1
z = 1
Now put z = 1 in equation (4)
-y+3=1
-y = -2
y = 2
Hence, the values of x,y and z are -1, 2 and 1 respectively.
(5/4)•(4/3)•(3/5)
So you multiply all of them basically
The First One
The Third One
The Forth One
The others result in a lower number than what they are supposed to be. The 3 correct ones end with the exact number of the equations solution number.
Well what i think you're asking here...I apologie if I'm wrong but what I did was
f(-1) = 4 * 7^t = 4/7
and
f(2) = 4 * 7^t = 196.
Is this what you wanted if not I can...try another way.
Answer 2.8
Step-by-step explanation:
yeah