Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Assuming you want to solve for x the result can vary. The result can be shown in multiple forms. Hope this helps!
Inequality Form:
−5≤x≤2
Interval Notation:
[−5,2]
(1,-3)(3,-5)
slope = (-5 - (-3) / (3 - 1) = (-5 + 3) / 2 = -2/2 = -1 <==
The circumference of a circle is calculated through the equation,
C = 2πr
where C is circumference and r is radius. For this item, I assume that 12 in is the radius such that,
C = 2π(12 in) = 24π
Thus, the circumference of the circle is 24π inches.
24% of 225 is 54, so you do 225+54=279 so 279 is the correct answer :)
