Question

If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

Answer 1

ANSWER

$(g \circ \: f)(0) = - 216$

EXPLANATION

The functions are:

$f(x) = 2x - 6$

$g(x) = {x}^{3}$

$(g \circ \: f)(x) =g(f(x))$

$(g \circ \: f)(x) =g(2x - 6)$

We substitute f(x) into g(x) to obtain:

$(g \circ \: f)(x) =(2x - 6)^{3}$

We now substitute x=0 to obtain;

$(g \circ \: f)(0) =(2(0) - 6)^{3}$

$(g \circ \: f)(0) =(- 6)^{3}$

This simplifies to:

$(g \circ \: f)(0) = - 216$