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2 years ago

A wave with a height of 5 feet and a wavelength of 10 feet has a wave base of

Mathematics

2 answers:

Sergeeva-Olga [200]2 years ago

7 0

Answer:

Step-by-step explanation:

EleoNora [17]2 years ago

4 0

Answer:

C. 5 feet

Step-by-step explanation:

If a wave with a height of 5 feet and a wavelength of 10 feet has a wave base of 5 feet.

B = x/2 = 10ft/2 = 5 feet

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Y varies directly as x y = 120 when x = 8 find y when x = 14

ANTONII [103]

Answer:

y = 120

Step-by-step explanation:

this is the formula

y = kx

now insert the numbers to find k

120 = k8

120/8

k = 15

now insert 15 into the equation where k was

y = 15 x 14

y = 210

3 0

2 years ago

Give an example of an equation that is true.

bonufazy [111]

Answer:

5 + 4 = 9

Step-by-step explanation:

7 0

2 years ago

A rectangular prism has a base area of 56 square feet and a volume of 840 cubic feet. The length of the base is longer than the

katovenus [111]

The answer is 8 ft.

The base area of rectangular prism is: A = l * w = 56 ft²
<span>The length of the base is longer than the width: l > w

The volume of the prism is: V = l * w * h = 840 ft</span>³
<span>The sum of the length and width of the base is equal to the height of the pyramid: l + w = h

So:
</span>l * w = 56
l * w * h = 840
___
56 * h = 840
h = 840 / 56
h = 15 ft

Now, we know that
l + w = 15 ⇒ w = 15 - l
l * w = 56
___
l * (15 - l) = 56
15l - l² = 56
0 = l² - 15l + 56

Or: l² - 15l + 56 = 0

Let's solve the quadratic function:
l = (-b +/-√(b² - 4ac)/(2a)
= (15 +/-√(-15)² - 4 * 1 * 56))/(2*1)
= (15 +/- √(225 - 224))/2
= (15 +/- √1)/2
= (15 +/-1)/2

l = (15+1)/2 = 16/2 = 8
or
l = (15-1)/2 = 14/2 = 7

If l = 8, then w = 15 - 8 = 7. So, l > w
If l = 7, then w = 15 - 7 = 8. So, l < w

Therefore, l = 8 ft.

6 0

2 years ago

8pq + 20qr – 16s factorise plz

Dafna1 [17]

Answer:

4(2qp + 5qr - 4s)

Step-by-step explanation:

8pq + 20qr – 16s

we can use 4 as a common factor between these numbers.

8/4 = 2

20/4 = 5

16/4 = 4

4(2qp + 5qr - 4s) is the most factorized answer we can get

8 0

2 years ago

A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const

Ludmilka [50]

Answer:

$0.609 \leq \sigma \leq 0.772$

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation

s=0.68 represent the sample standard deviation

$\bar x =98.90$ represent the sample mean

n=98 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=98-1=97$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.