Answer:
(2*3)=6; 60= (2*3)*2*5 (prime factorization)
The numbers in the parenthesis can't be taken out because they are the HCF
So just move the 2 and the 5 on both sides and you'll get two pairs that are (6,30) and (12,30)
Answer:
10
Step-by-step explanation:
10(4-7)
-------------
-(4-1)
Parentheses first
10(-3)
----------------
-(3)
Cancel the negative 3's
10(1)
------------
(1)
10
Step-by-step explanation:
Since the 3 and 7 have 21 as a common multiple you can divide 21 by the denominator of each term and then multiply it by the numerator which get you while numbers