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2 years ago

A park is 4.6 miles long and 2.7 miles wide.What is the total distance around the park

Mathematics

1 answer:

levacccp [35]2 years ago

6 0

The distance around the park is the perimeter.

To find the perimeter add two lengths plus two widths:

Perimeter = 4.6 +4.6 + 2.7 +2.7 = 14.6 miles

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koban [17]

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so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

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Answer:

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algol [13]

Alright.
So let's say the number of adults is x.
Therefore, the number of boys is 7x + 1.
And then the total amount of girls is 3.5x + 0.5
So then:
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