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2 years ago

Can someone help me with this question?

Mathematics

1 answer:

Masteriza [31]2 years ago

6 0

Answer:

V=2c

Step-by-step explanation:

$\\[Looking at the relationship of the numbers in the table, we can see which ones will work right off the bat.]\\[Our first numbers are both zero, so we cant do anything significant there.]\\[Next row, however, we can start doing the process of elimination.]\\\left[\begin{array}{ccc}1&2\\2&4\\3&6\\4&8\\5&10\end{array}\right]\\ \\[After plugging in the formulas to see if they're true, the only one that works every time is V=2c.]\\[That is your answer.]$

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Use the diagram below & your knowledge of inscribed angles of a quadrilateral to label the measures of EACH inscribed angle

Marrrta [24]

Answer:

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Step-by-step explanation:

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8 0

1 year ago

A circular swimming pool is 21 feet in

Aleksandr [31]

Answer:

G. 66 feet

Step-by-step explanation:

Radius = 21/2 = 10.5

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2 years ago

Help anyone please i need it

zheka24 [161]

Answer:

The sum is equal to $-905,200$

Step-by-step explanation:

we know that

The formula to calculate the sum is equal to

$Sn=n\frac{(a1+an)}{2}$

In this problem

$n=775$ -----> number of terms

a1 is the first term

$a1=(-3(1)-4)=-7$

an is the last term

$an=(-3(775)-4)=-2,329$

substitute

$Sn=775\frac{(-7-2,329)}{2}=-905,200$

4 0

2 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$