The copper wire was sanded before burning in order to make sure that copper metal was exposed on the surface of the wire.
Answer: B
Explanation
The copper wire when placed in atmosphere without coating leads to oxidation of copper metal with respect to the impurities present in the atmosphere.
As copper is electropositive in nature, so electronegative ions present in the universe will try to react with copper and the copper will react easily with other elements.
So generally copper wire is coated with color or polymer coating.
In this case, the copper wire without any coating is sanded, so that the eddy sheets or polishing materials on friction with copper wire will remove the impurities by the electrostatic law of conservation of charges and charge transfer.
As the impurities are removed when copper wire is sanded, the copper atoms will be exposed on the surface of the wire leading to burning of copper in the copper wire.
you are right on all the ones you did
Answer: Total number of Protons PLUS Neutrons
Explanation:
Hopes that helps
The answer is 2300 mg which is equal to one teaspoon of salt
Answer:
- 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)
- 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
- 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
- 2a) Calcium hydroxide and hydrogen gas
- 2b) Tin(II) silicate and Lead(IV) permanganate
- 2c) Magnesium oxide and water
- 2f) Calcium chloride and iodine
- 2g) Strontium phosphite and cesium nitride
- 2h) Carbon dioxide, water, and sulfur dioxide
- 2i) Iron oxide(III) and carbon dioxide
- 2j) Magnesium acetate and hydrogen gas
Explanation:
1. For each of the following, convert the word equation into a formula equation, BUT do not balance!
a) Barium chlorate → Barium chloride + Oxygen
<u>1. Chemical formulas</u>
Barium chlorate:
- It is a salt: an ionic compound.
- Barium has oxidation state +2
- Chlorate is the ion ClO₃⁻
- Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
- Chemical formula Ba(ClO₃)₂
- It is solid: Ba(ClO₃)₂(s)
Barium chloride:
- It is a salt: an ionic compount
- Barium has oxidation state +2
- Chlorine is in oxidation state -1
- Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
- BaCl₂
- It is solid BaCl₂(s)
Oxygen:
- It is a diatomic gas molecule
- O₂(g)
<u />
<u>2. Write the unbalanced molecular equation:</u>
- BaClO₃(s) → BaCl₂(s) + O₂(g)
b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride
<u>1. Chemical formulas</u>
Chlorine:
- It is a diatomic gas molecule
- Cl₂(g)
Potassum nitride
- Potassium has oxidation state +1
- Nitrogen is with oxidation state +3
- Swap the oxidation states
- K₃N
- It is solid: K₃N(s)
Nitrogen:
- It is a diatomic gas
- N₂(g)
Potassium chloride
- It is a salt (ionic compound)
- Potassium has oxidation state +1
- Chlorine is in oxidation state -1
- Swap the oxidation numbers
- KCl
- It is solid: KCl(s)
<u>2. Write the unbalanced molecular equation</u>
<u />
- Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate
<u>1. Chemical formulas</u>
Sodium nitride
- It is a salt (ionic compound)
- Sodium has oxidation state +1
- Nitrogen is with oxidation state -3
- Swap the oxidation numbers
- Na₃N
- It is in aqueous solution
- Na₃N (aq)
Aluminum bromate
- Salt
- Aluminum has oxidation state +3
- Bromate is the ion BrO₃⁻
- Swap the oxidation states
- Al(BrO₃)₃ (aq)
Aluminum nitride
- Both Al and N have oxidation state 3, which simply
- AlN(s). It is not soluble in water.
Sodium bromate
<u>2. Write the unbalanced molecular equation</u>
- Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
<h2>
This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2>
</h2><h2>
The attached file contains the complete answer.</h2>
