By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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Answer:
<em><u>x = 249</u></em>
Step-by-step explanation:
Step 1. Combine like terms
1/3x + 166 = x
Step 2. Subtract 1/3x from both sides
166 = 2/3x
Step 3. Multiply it all by 3/2 to get rid of the 2/3
249 = X
Answer:$3
Step-by-step explanation:
Answer:
Lets break it you add -45 to 10 and get -35 then you add -20 to 20 making 0 so the answer is -35
Step-by-step explanation:
Answer:
To be honest I think its C but it may be A
Step-by-step explanation: