A mass is set oscillating horizontally, with an amplitude of 11.3 cm and a period of 0.702 sec. What is the velocity of the part
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Answer:
The magnitude of the lift force L = 92.12 kN
The required angle is ≅ 16.35°
Explanation:
From the given information:
mass of the airplane = 9010 kg
radius of the airplane R = 9.77 mi
period T = 0.129 hours = (0.129 × 3600) secs
= 464.4 secs
The angular speed can be determined by using the expression:
ω = 2π / T
ω = 2 π/ 464.4
ω = 0.01353 rad/sec
The direction
θ = 16.35°
The magnitude of the lift force L = mg ÷ Cos(θ)
L = (9010 × 9.81) ÷ Cos(16.35)
L = 88388.1 ÷ 0.9596
L = 92109.32 N
L = 92.12 kN
Explanation:
Given parameters:
Force = 30N
Weight Susan = 45kg
Weight of Dad = 100kg
Unknown:
Acceleration of Susan = ?
Acceleration of Dad = ?
Solution:
Force = mass x acceleration
Acceleration =
Acceleration of Susan = = 0.67m/s²
Acceleration of Dad = = 0.3m/s²
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Acceleration brainly.com/question/3820012
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