If you push a shopping cart with all of your strength will it move faster if it's empty or full of items? Explain

John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.

aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. $t=6000\ s$ is the total time taken in the trip

c. $d=126000\ m$ is the total distance

d. $s=54000\ m$ towards right from the starting point.

e. $v_a=21\ m.s^{-1}$

f. $\vec v_a=9\ m.s^{-1}$ towards right.

Explanation:

a.

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

b.

Total time of round trip when we're given:

distance travelled to the right, $d_r=90000\ m$

speed while travelling to the right, $v_r=25\ m.s^{-1}$

time spent at gas station, $t_g=600\ s$

time spent while travelling back towards the left, $t_l=30\times 60=1800\ s$

speed while travelling to the left, $v_{_l}=20\ m.s^{-1}$

Now time taken for travelling towards right:

$t_r=\frac{d_r}{v_r}$

$t_r=\frac{90000}{25}$

$t_r=3600\ s$

Therefore total time taken in the round trip:

$t=t_r+t_l+t_g$

$t=3600+600+1800$

$t=6000\ s$

c.

Now, distance travelled towards left:

$d_l=v_{_l}\times t_l$

$d_l=20\times1800$

$d_l=36000\ m$

Therefore total distance:

$d=d_l+d_r$

$d=36000+90000$

$d=126000\ m$

d.

Now, total displacement:

$s=d_r-d_l$

$s=90000-36000$

$s=54000\ m$ towards right from the starting point.

e.

Average speed:

$v_a=\frac{d}{t}$

$v_a=\frac{126000}{6000}$

$v_a=21\ m.s^{-1}$

f.

Average velocity:

$\vec v_a=\frac{s}{t}$

$\vec v_a=\frac{54000}{6000}$

$\vec v_a=9\ m.s^{-1}$ towards right.

4 0

2 years ago

Heated air inside a hot-air balloon causes it

zysi [14]

Answer:

There is pressure on both the in and outsides of the balloon: high inside and low outside, respectively. In terms of air mass, high pressure has greater activity and tends to move upward (balloon rises); whereas low presssure, being slower, descends (balloon descends).

Explanation:

6 0

1 year ago

Read 2 more answers

If the archerfish spits its water 60. degrees from the horizontal aiming at an insect 2.0 m above the surface of the water, how

MA_775_DIABLO [31]

Using the kinematic equations below, we can calculate the initial velocity required. Angle of projectile = 60 degrees Acceleration due to gravity (Ay) = -10 m/s^2 (negative because downward) Height of projectile (Dy) = 2m Vfy^2=Voy^2 +2*Ay*Dy Vfy = 0 m/s because the vertical velocity slows to zero at the height of its trajection. So... 0 = Voy^2 + 2(-10)(2) 0 = Voy^2 - 40 40 = Voy^2 Sqrt40 = Voy 6.32 m/s = Voy THIS IS NOT THE ANSWER. THIS IS JUST THE INITIAL VELOCITY IN THE Y DIRECTION. Using trigonometry, Tan 60 = Voy/Vox. Tan 60 = 6.32/Vox. Vox*Tan 60 = Vox Vox = 10.95 m/s. Now, using Vox = 10.95 and Voy = 6.32, we can use pythagorean theorem to find the total Vo. A^2 +B^2 = C^2 10.95^2 + 6.32^2 = C^2 Solving for C = 12.64 m/s This is the velocity required to hit the surface. You can also calculate a bunch of other stuff now using the other kinematic equations. V = 12.64 m/s

5 0

2 years ago

Read 2 more answers

What is the force of impact of a 100 kg diver who falls into a swimming pool and hits the surface of the water and comes to a st

Simora [160]

Answer:

F = 53153.36[N]

Explanation:

In order to solve this problem, we must first use the principle of conservation of energy which is transformed from potential energy to kinetic, in this way we can determine the velocity at which the person enters the water.

$E_{pot}=E_{kin}\\m*g*h=\frac{1}{2}*m*v^{2}$

where:

m = mass = 100 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 9 [m]

v = velocity [m/s]

Now replacing we can determinate the velocity.

$v^{2}=2*g*h\\v=\sqrt{2*g*h}\\v=\sqrt{2*9.81*9}\\v = 13.28[m/s]$

Then we can calculate the momentum which can be calculated as the product of force by time, this momentum is also equal to the product of mass by velocity.

$P=m*v\\and\\P =F*t\\F*t=m*v$