Answer:
length of rectangle = 5
width of rectangle = 5
Area of rectangle = 25
Step-by-step explanation:
Since the length of the rectangle is "x", and the value of the area is given by the product of the length "x" times the width "10-x", indeed, the area "y" of the rectangle is given by the equation:
Now, they tell us that the area of the rectangle is such that coincides with the maximum (vertex) of the parabola this quadratic expression represents. So in order to find the dimensions of the rectangle and therefore its area, we find the x-coordinate for the vertex, and from it, the y-coordinate of the vertex, which is the rectangle's actual area.
Recall that the formula for the x of the vertex of a quadratic of the form :
is given by the formula:
which in our case gives:
Therefore, the length of the rectangle is 5, and its width (10-x) is also 5.
The area of the rectangle is therefore the product of these two values: 5 * 5 = 25
Which should coincide with the value we obtain when we replace x by 5 in the area formula:
Its going more horizontal because the slope has you go up 1 and right 4, meaning you are going right more than you are going up
Answer:
A
Step-by-step explanation:
Divide 6.8ft by 4in then you get 1.7 and the multiply 15 an 14 by 1.7 then you get 25.5 and 23.8 then multiply 25.5 with 23.8 and get 606.9
Since x=x, this is an isosceles right triangle. By the Pythagorean Theorem:
h^2=a^2+b^2 (the hypotenuse squared is equal to the sum of the squared sides)
5^2=x^2+x^2
25=2x^2
2x^2=25
x^2=25/2
x=√(25/2)
x=5/√2 now if we rationalize the denominator...
x=(5√2)/(√2√2)
x=(5√2)/2
Answer:
2a^2b(5a-3b)
If not then the other way is
5a-3b
Step-by-step explanation:
The GCF of 10a^3b and -6a^2b^2 is 2a^2b
So divide by that you will get
2a^2b(5a-3b)