Hi! So, the one that doesn't belong is a) y = 4x.
I think that this doesn't belong because every other option has a number after the variable (I forget the exact term for it but it's like +7, +4, and -1 for the rest of the options)
Please let me know how I can further help you :)
(
-6n-20=-2n+4-12n
-6n-20=-14n+4
+6n +6n
-20=-8n+4
-4 -4
-24=-8n
/8 /8
n=-3
-
Hello,
f(x)=2x^2-3x+4
f(3a)=2(3a)^2-3*(3a)+4=2*9a²-9a+4=18a²-9a+4
PART A:
The given quadratic equation is 2x²-10x-8=0
The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c
From the given equation, we have
a = 2
b = -10
c = -8
Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164
The radicand is >0 hence the quadratic equation has two distinct roots
PART B:
4x²-12x+5 = 0
We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12
The pair of number is -2 and -10
Rewriting the equation
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0
2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2
