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2 years ago

If ABF= (7x + 20), FBC=(2x - 5), and ABC= 159", find the value of x. x =

Mathematics

1 answer:

s2008m [1.1K]2 years ago

3 0

Given :

∠ABF = ( 7x + 20 )°

∠FBC=(2x - 5)°

∠ABC= 159°

To Find :

The value of x .

Solution :

Assuming B the center of a circle .

So , all three given angles must be added to 360° .

$(7x+20)+(2x-5)+159=360\\\\9x+15+159=360\\\\x=20.67$

Therefore , the value of x is 20.67° .

Hence , this is the required solution .

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Aleksandr-060686 [28]

The answer is d which is 6/5

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3 years ago

Solve this linear system 28x + 44y = 964.40 21x + 33y = 723.30

Sladkaya [172]

28x + 44y = 964.40

21x + 33y = 723.30

Let's multiply the first equation by 4 and the second by -4

84x + 176y = 3857.6

-84x - 132y = -2893.2

Add the equations together.

0 + 44y = 964.4

Simplify

44y = 964.4

Divide both sides by 44

y = 964.4/44

Since we have the value of y, let's plug 964.4/44 into y for the first equation.

28x + 44(964.4/44) = 964.40

Simplify the left side

28x + 964.4 = 964.4

Subtract 964.4 from both sides

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Divide both sides by 0

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In conclusion,

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2 years ago

The midpoint of segment AB is (4, 2). The coordinates of point A are (2, 7). Find the coordinates of point B.

erastovalidia [21]

Answer:

<h3>The option B) is correct</h3><h3>Therefore the coordinate of B $(x_2,y_2)$ is (6,-3)</h3>

Step-by-step explanation:

Given that the midpoint of segment AB is (4, 2). The coordinates of point A is (2, 7).

<h3>To Find the coordinates of point B:</h3>

Let the coordinate of A be $(x_1,y_1)$ is (2,7) respectively
Let the coordinate of B be $(x_2,y_2)$
And Let M(x,y) be the mid point of line segment AB is (4,2) respectively
The mid-point formula is

Now substitute the coordinates int he above formula we get
$(4,2)=(\frac{2+x_2}{2},\frac{7+y_2}{2})$
Now equating we get

$4=\frac{2+x_2}{2}$ $2=\frac{7+y_2}{2}$

Multiply by 2 we get Multiply by 2 we get

$4(2)=2+x_2$ $2(2)=7+y_2$

$8=2+x_2$ $4=7+y_2$

Subtracting 2 on both

the sides Subtracting 7 on both the sides

$8-2=2+x_2-2$ $4-7=7+y_2-7$

$6=x_2$ $-3=y_2$

Rewritting the above equation Rewritting the equation

$x_2=6$ $y_2=-3$

<h3>Therefore the coordinate of B $(x_2,y_2)$ is (6,-3)</h3><h3>Therefore the option B) is correct.</h3>

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