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2 years ago

WILL PICK BRAINIEST ANSWER AND u have to be my friend what is 5 1/3 + 4 2/5

Mathematics

2 answers:

Jobisdone [24]2 years ago

8 0

The answer is 146/15.

Stells [14]2 years ago

7 0

Change the mixed numbers from mixed numbers into fractions, so you would have:
16/3 + 22/5
Now to add these two together, they have to have the same denominator. To do that, multiply 16/3*5/5 and 22/5*3/3 and your new terms would be:
80/15 + 66/15
Now you can add the numerators together:
146/15
and simplify for your answer:
9 11/15

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Read 2 more answers

Find the probability of each event.

jeka57 [31]

Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

The coin is fair, hence p = 0.5.

The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098$

$P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001$

Hence:

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108$

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

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