Explanation:
(a) The given data is as follows.
Temperature (T) = 
= (25 + 273) K = 298 K
= 43000 J/mol
Since, both the liquid and vapors are at equilibrium. Therefore, change in free energy will be calculated as follows.
= 0
43000 - 
= 0
= -144 J/mol K
Negative sign indicates an increase in entropy of the system.
Now, for 1 mole of 
is as follows.
= 144 J/K
So, 
- 214 = 144 J/k
= 358 J/K
Therefore, we can conclude that entropy of vapor is 358 J/K.
(b) As we know that intensive variable are the variables which do not depend on the amount of a substance.
So, in the given situation only temperature will act as an intensive variable that will be required to completely specify the vapor-liquid mixture of .
Answer:
reactive. hope this helps
Answer:
There will 3.95 grams of Na2 and H2O that should be added to form a concentric required solution.
Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:
54.3 mm = 5.43 cm
Now, we determine the number of gold atoms that will be present in this:
5.43 / 1 x 10⁻⁹
There will be 5.43 x 10⁹ atoms
We now determine the number of moles this is by:
one mole = 6.02 x 10²³ atoms
Moles = 5.43 x 10⁹ / 6.02 x 10²³
Moles = 9.01 x 10⁻¹⁵ moles
The molar mass of gold is 197 g/mol
The mass is 9.01 x 10⁻¹⁵ * 197
The mass of the strand is 1.76 x 10⁻¹² grams
Answer:
H- hydrogen
Explanation: Hydrogen is in the first group meaning that it only has 1 valence electron and 1 energy level
