3:5 =3/5
3/5=4.16/x
using cross multiplication,
5(4.15)=3(x)
20.8=3x
x=108/15
thus, 4.16÷104/15 =3/5
X6 – 9x3 + 8 = 0
let u = x^3
u^2 - 9u + 8 = 0
(u-8)(u-1) = 0
u = 1,8
back substitute
1 = x^3
8 = x^3
<span>x = 1 , 2</span>
The shortest value has to be greater than 6 and less than 22 in order for 22 to be one of the 2 longer sides.
