Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Donny drove 70 miles.
Since 60 miles per hour is 1 mile a minute so for in 45 minutes he drove 45 miles. After he drove for 50 miles for thirty minutes so in totally he drove 25 since 50 divided by two is 25.
so all those quadratics have their parent y = x², which has the graph of a "bowl".
and depending on the coefficient, the bowl is wider or not.
the larger the coefficient, the narrower the bowl, the smaller the coefficient, the wider the bowl.
well, 1/2 is smaller then 2, thus y = (1/2)x² is wider than y = 2x².
Answer: a) 15625, b) 0.2, c) 625, d) 0.008.
Step-by-step explanation:
Since we have given that
a) 
As we know that
So, it becomes,
(b) 
So, it becomes,
(c) 
As we know that
So, it becomes,
(d) 
Hence, a) 15625, b) 0.2, c) 625, d) 0.008.
Answer:
2π
Step-by-step explanation:
Area = πr^2
= π2^2
= 4π
4π is the area of the whole circle, so divide it in half to get the semicircle.
<u>= 2π</u>
