Pretty sure it's A ?? That's what I got. I'm taking this right now.
Answer:
Step-by-step explanation:
Rewrite this quadratic equation in standard form: 2n^2 + 3n + 54 = 0. Identify the coefficients of the n terms: they are 2, 3, 54.
Find the discriminant b^2 - 4ac: It is 3^2 - 4(2)(54), or -423. The negative sign tells us that this quadratic has two unequal, complex roots, which are:
-(3) ± i√423 -3 ± i√423
n = ------------------- = ------------------
2(2) 4
Step-by-step explanation:
You can use PEMDAS to solve this problem from left to right.
First, do 15 ÷ 3 to get 5.
Next, do 2 x 10 to get 20.
Lastly, add 5 and 20 to get 25.
<u>15 ÷ 3</u> + 2 x 10
5 + <u>2 x 10</u>
<u>5 + 20</u>
25
Laila=l
Tom=t
Dan=d
l=t+14
l=d-5
l+t+d=51
In terms of l:
d=l+5
t=l-14
So:
l+l+5+l-14=51
3l+5-14=51
3l-9=51
3l=60
l=20
d=25
t=6
Hope this helps :)
Answer:
5
Step-by-step explanation:
The radius is 5.
All I do was think of the center-radius form a circle
(x-h)^2+(y-k)^2=r^2
x^2 + y^2 =25
(x-0)^2+(y-0)^2=5^2
The center is (0,0) and the radius is 5.
So a point on the circle (x,y) has a distance of 5 from the center
and the center's case here is (0,0).
