Answer:
A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).
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Answer:
4x2−12x+9=0
Step-by-step explanation:
The equation, 2x2+x+3=0, does not have a solution
The equation, x2+5x−3=0, equals -5/2+1/2√37 and -5/2+-1/2√37
The equation, x2−5x+4=0, equal 1 and 4
The equation, 4x2−12x+9=0, equals only 3/2
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Answer:
11
Step-by-step explanation:
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