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2 years ago

What is the value for ƒ(x) = 3x^2+1 when x= 1/2 3 6 9 15

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

5 0

None of your answers above will answer the question. The proper value for x = 1/2 is 7/4. The work for this is below.

f(x) = 3x^2 + 1

f(1/2) = 3(1/2)^2 + 1

f(1/2) = 3(1/4) + 1

f(1/2) = 3/4 + 1

f(1/2) = 7/4

I assume you may have missed something in typing, but 7/4 would be your answer.

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A line passes through $A(1,1)$ and $B(100,1000)$. How many other points with integer coordinates are on the line and strictly be

jonny [76]

Answer:

Step-by-step explanation:

Integers are whole numbers or opposite of whole numbers.

The slope is 1.

How?

Change of y is 100-1=99.

Change of x is 100-1=99.

The slope is 99/99=1 or 1/1.

So if we start at (1,1) and we rise 1 and run 1 right, we get (2,2).

If we do that again from (2,2) we get (3,3).

Following the pattern of going up 1 and right from each new location discovered we get all the of these points:

Start (1,1)

(2,2)

(3,3)

(4,4)

(5,5)

(6,6)

....

(96,96)

(97,97)

(98,98)

(99,99)

end (100,100)

So we just need to count all the numbers from 2 to 99.

99-2+1

97+1

7 0

2 years ago

What is the equation of the parabola?

Neporo4naja [7]

Answer:

y = -1/8 x² + 5

Step-by-step explanation:

Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)

basic formula: y = a(x - h)² + k

y = a (x-0)² + 5

y = ax² + 5 pass (4,3)

3 = 16a + 5

a = (3-5)/16 = -1/8

equation: y = -1/8 x² + 5

check: pass another point (-4,3)

-1/8 * (-4)² + 5 = -2 + 5 = 3

5 0

2 years ago

What is 50/80 in simplest form? Thanks for your awesome help people

Sliva [168]

The answer is 5/8 because they both are divisable by 10

7 0

2 years ago

How do you do this? with work.

Rashid [163]

Answer:

i don't know

Step-by-step explanation:

so i have 20 the answer i thin

7 0

2 years ago

Find the first five terms of the sequence given the following recursive formula:

forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

$a_1=-3,$ , $a_2=-7$ and $a_n=a_{n-2}-2a_{n-1}$ .

When n=3, we obtain;

$a_3=a_{3-2}-2a_{3-1}$ .

$\implies a_3=a_{1}-2a_{2}$ .

$\implies a_3=-3-2(-7)$ .

$\implies a_3=11$ .

When n=4

$\implies a_4=a_{2}-2a_{3}$ .

$\implies a_4=-7-2(11)=-29$ .

When n=5

$\implies a_5=a_{3}-2a_{4}$ .

$\implies a_4=11-2(-29)=69$ .

Therefore the first five terms are;

-3,-7,11,-29,69

5 0

2 years ago