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2 years ago

Can somebody help me with this math question?

Mathematics

1 answer:

Sliva [168]2 years ago

5 0

Answer: UV and TW

Step-by-step explanation:

They do not intersect and they are not parallel, hope this helps!

<!> Brainliest is appreciated! <!>

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3/8 of the students and Mrs. Miles class rides a bus there are 24 students in the class how many students ride the bus

irina1246 [14]

9 students ride the bus.

3 0

2 years ago

Brainliest, thanks, five stars

lutik1710 [3]

Answer:

Option C) 16(0.5x - 0.75y + 2)

Step-by-step explanation:

16(0.5x - 0.75y + 2) = 16*0.5x - 0.75y*16 + 2 *16

= 8.0x - 12.0y + 32

= 8x - 12y + 32

5 0

2 years ago

Show me how you solve it

julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

Law of Exponent I

$\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} }$

Therefore:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} }$

Law of Exponent II

$\displaystyle \large{( {a}^{m} ) ^{n} = {a}^{m \times n} }$

Thus:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{5 \times 4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{20} }$

7 0

2 years ago

Can you please help me on this ive been on this forever

Readme [11.4K]

Answer:

∠d , ∠f

Step-by-step explanation:

triangle ABC is similar to triangle DEF

∠A is same as angle ∠D as it is the opposite to it

∠c is same as ∠F as it is the opposite to it

6 0

2 years ago

a car dealership sells 48 cars of the same model in one month. the average price of each car is $25,000 with a maximum variance

Umnica [9.8K]

Answer:

Range= $144,000

Step-by-step explanation:

The least amount for each car is 22,000 and the highest is 25,000

so assuming the dealer sells all of them the lowest price, the revenue would be, $1,056,000 (that would be the lowest revenue) and assuming he sells all the cars at the highest price, the dealer will get a revenue of $1,200,000. So the lowest revenue is 1,056,000 and the highest revenue is 1,200,000. So to find the range subtract the highest revenue by the lowest and you’ll get $144,000.

7 0

2 years ago