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2 years ago

Prokaryotic flagella has the same internal structure as eukaryotic flagella.

2 answers:

5 0

The internal structure of prokaryotic flagella is the same as the internal structure of eukaryotic flagella. Prokaryotic cells do not contain endoplasmic reticulum, Gold bodies, mitochondria, plastids, or membrane-bound vesicles.

Alex2 years ago

4 0

Answer:

No, they do not have the same internal structure.

Explanation:

Prokaryotes lack the presence of a nucleus and a cell wall. The size and complexity of the ribosomes and how the cells reproduce are different in prokaryotes and eukaryotes. In eukaryotic cells, the ribosomes are bigger, more complex and bound by a membrane.

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Which is the correct order of levels of organisation in organisms, from least complex to most complex?

yanalaym [24]

Answer:

The biological levels of organization of living things arranged from the simplest to most complex are organelle, cells, tissues, organs, organ systems, organisms, populations, communities, ecosystems, and biosphere.

Explanation:

I found the answer on the internet :)

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2 years ago

The presence of excessive body and facial hair in women

Ad libitum [116K]

Answer:

:/ what about it? is this your question? if so you need to add more detail then that so people know what your talking about

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1 year ago

A planet has a mass of 5.97 x 1024 kg and a radius of 6.38 x 106 m. Find the weight of a 65.0 kg person at 1000 km above the sur

mote1985 [20]

<u>Answer:</u> The weight of the person above the surface of a planet is 635.83N.

<u>Explanation:</u>

To calculate the weight of a person, we use the formula:

$w=mg$ ....(1)

where,

w = weight of an object

m = mass of the person = 65kg

g = acceleration due to the gravity of the planet

For the calculation of weight, we need to first find the acceleration due to gravity and for that we use the formula:

$g=\frac{GM}{r^2}$

where, g = acceleration due to gravity = $?m/s^2$

G = Universal gravitational constant = $6.67\times 10^{-11}Nm^2/kg^2$

M = mass of the planet = $5.97\times 10^{24}kg$

r = distance of the person from the planet = $6.38\times 10^6m$

Putting values in above equation, we get:

$g=\frac{(6.67\times 10^{-11}kgm/s^2.m^2/kg^2)(5.97\times 10^{24}kg)}{(6.38\times 10^6m)^2}\\\\g=9.782m/s^2$

Putting this value in equation 1, we get:

$w=65kg\times 9.782m/s^2=635.83N$

Hence, the weight of the person above the surface of a planet is 635.83N.

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2 years ago

PLEASE HELP AND ANSWER AS MANY AS YOU CAN THIS IS MY FINAL EXAM

Fantom [35]

Answer:

2. Direct, 3. 1 2 and 3 I couldn't find 1 srry. :)

Explanation:

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2 years ago

Read 2 more answers

Both mitiosis and meiosis begin with a diploid cell that contains replicated chromosomes. explain the main difference between th

xz_007 [3.2K]

The main difference is that mitosis occurs in body cells and meiosis occurs in sex cells. Mitosis produces identical daughter cells and meiosis produces genetically different daughter cells.

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2 years ago