Answer:
15205.3
Step-by-step explanation: H=30 R²=484 3.14=π →= rounded up to tenth V = Volume
<em><u>formula (no numbers): H x R² x π ÷</u></em><u> </u>
<u> (or 3) </u><em><u>= V</u></em>
<u><em>how i got the answer : 30 x 484 x 3.14 ÷ 3 = 15205.31 → 15205.3</em></u>
If T and V are complementary angles, their sum is 90°.
V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2
The value of X is 16.
Answer:
x² is HCF (Height common factor)
Step-by-step explanation:
Given:
x² , x³
Find:
HCF (Height common factor)
Computation:
HCF (Height common factor) is uused to find Height common factor from the given numbers.
x² , x³
Takling x² as common
x² (1 , x)
So,
x² is HCF (Height common factor)
Answer:
46/ 67
Step-by-step explanation:
The numbers of students irrespective of grades is;
The sum of the last roll of numbers:
10+24+ 33+ 67 = 134
The number of males irrespective of grades is the sum of the numbers in the male row ;
7 +20+ 14 +41= 82
The numbers of students with grade A is the first column at the last row and is 10;
Hence;
the probability that the student was male OR got an 'A' is
the probability that the student was male plus the probability that he/she got an 'A'.
The probability that it's a male is ;
Number of males/ total number of students
=82/134
The probability that he got an A is;
The number of students that got A/ the total number of students;
10/134
Hence
the probability that the student was male OR got an 'A' is;
82/ 134 + 10/134 = 92/134 = 46/ 67
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