The LCM of three numbers is 7920 and their GCD is 12. Two of the numbers are 48 and 264. Using factor notation find the third nu
mber if one of its factors is 9.
1 answer:
Answer:
The third number is 180.
Step-by-step explanation:
Let the third number be 9x where x is an integer.
48 = 2*2*2*2*3
264 = 2*2*2*3*11
9x = 3*3*x
2*2*2*2*3*3*11*x = 7920y where y is an integer
1584x = 7920y
so x = 7920y / 1584= 5y.
Now the GCD is 12 so x must have 4 as one of its factors.
Also x is a multiple of 5 so it could be 20 then y would be 4.
If x = 20 then the third number is 9*20 = 180.
This checks out OK.
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V1 - velocity first train
v2 - velocity second train
v2 > v1
v2 - v1 = 17 mph
We know, that:
![s_1+s_2=210 \ [miles] \\ \\ t_1=t_2=2h](https://tex.z-dn.net/?f=s_1%2Bs_2%3D210%20%5C%20%5Bmiles%5D%20%5C%5C%20%5C%5C%20t_1%3Dt_2%3D2h)
So:
NOw we've got simple system of equations:
![+\begin{cases} v_2-v_1=17 \\ v_2+v_1=105\end{cases} \\ \\ 2v_2=122 \qquad /:2 \\ \\ v_2=61 \qquad [mph] \\ \\ v_2-v_1=17 \\ \\ 61-v_1=17 \\ \\ v_1=44](https://tex.z-dn.net/?f=%2B%5Cbegin%7Bcases%7D%20v_2-v_1%3D17%20%5C%5C%20v_2%2Bv_1%3D105%5Cend%7Bcases%7D%20%5C%5C%20%5C%5C%202v_2%3D122%20%5Cqquad%20%2F%3A2%20%5C%5C%20%5C%5C%20v_2%3D61%20%5Cqquad%20%5Bmph%5D%20%5C%5C%20%5C%5C%20v_2-v_1%3D17%20%5C%5C%20%5C%5C%2061-v_1%3D17%20%5C%5C%20%5C%5C%20v_1%3D44)
Velocities of these trains are 61mph and 44mph
Well Jay has 20 phone numbers.
20j=13r-3x2 im not sure but i hope that helped a little.
To answer this question, simply input the values for g and h:
9/ (3) + 2 (6) + 5 = 9/ 3 + 12 + 5
= 9/ 20
Hope this helps!
Answer:
1/4 assuming x is not 0
Step-by-step explanation:
x^0 is 1 and 1/4 * 1 = 1/4
