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2 years ago

13

Am I correct? Will give brainliest!!

2 answers:

nevsk [136]2 years ago

7 0

Yes that would be the correct answer

Katarina [22]2 years ago

6 0

That is the correct answer

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archy bought 15 gallons of gas for $23.85. Joe bought 16 gallons of gas for $24.48. who paid less per gallon?

tekilochka [14]

Archy: 15 gallons ... $23.85
1 gallon ...$ x = ?

x * 15 = 1 * 23.85 /15
x = 23.85 / 15
x = $1.59 per gallon

Joe: 16 gallons ... $24.48
1 gallon ... $ y = ?

y * 16 = 1 * 24.48 /16
y = 24.48 / 16
y = $1.53 per gallon

Result: Joe paid less per gallon.

3 0

2 years ago

Help I am confused i don’t remember how to answer this.

krek1111 [17]

Answer:

5/6

Step-by-step explanation:

I hope this helps!

8 0

2 years ago

Read 2 more answers

Count the number of strings of length 9 over the alphabet {a, b, c} subject to each of the following restrictions.

Andrew [12]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document. I hope my explanation will help you in understanding this particular question.

Step-by-step explanation:

6 0

2 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

Can someone please give me the answer to this problem?

Alik [6]

X= 9/2, 15/2
decimal form: 4.5,-7.5
mixed number form: 4 1/2, -7 1/2

3 0

2 years ago