2 years ago

Find the derivative g(x)=ln(2x^2+1)

Mathematics

1 answer:

lana [24]2 years ago

8 0

Answer:

4x / (2x^2+1)

Step-by-step explanation:

g(x)=ln(2x^2+1)

Using u substitution

u= 2x^2 +1

du = 4x dx

g'(x) = d/du ( g(u) du)

We know that the derivative of ln(u) = 1/u since this is always positive

= 1/ u* du

Substituting x back into the equation

g'(x) = 1/(2x^2+1) * 4x

= 4x / (2x^2+1)

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