If it is a matter of which way you are going you could lean forward. It would help to put all the weight opposite of where you are falling.
Answer:
x = D (M/M-m) 2.41
Explanation:
a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation
F = g m₁m₂ / r²
Σ F = 0
F1- F2 = 0
F1 = F2
We set the reference system in the body of greatest mass (M) the planet
F1 = g m₁ M / x²
F2 = G m1 m / (D-x)²
G m₁ M / x² = G m₁ m / (D-x)²
M (D-x)² = m x²
MD² -2MD x + M x² = m x²
x² (M-m) -2MD x + MD² = 0
We solve the second degree equation
x = [2MD ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)
x = {2MD ± 2D √ (M² + (M-m) M)} / 2 (M-m)
x = D {M ± Ra (2M²-mM)} / (M-m)
x = D (M ± M √ (2-m/M)) / (M-m)
x = D (M / (M-m)) (1 ±√ (2-m/M)
Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root
x = D (M / (M-m)) (1 + √2)
x = D (M/M-m) 2.41
b) X = 2/3 D
x = D (M/M-m) 2.41
2/3 D = D (M/(M-m)) 2.41
2/3 (M-m) = M 2.41
2/3 M - 2/3 m = 2.41 M
1.743 M = 0.667 m
M/m = 0.667/1.743
M/m = 0.38
You have not provided choices, therefore, I can not provide an exact choice.
However, I will tell you the components of the given circuit and you can choose the one found in the choices you have.
The given circuit is composed of:
1- A battery:
It has the symbol of the long line and short line next to each other. The long line represents the positive pole while the short line represents the negative one. Battery is used to supply power to the circuit
2- An ammeter:
If has the symbol of an "A" in a circle. This device is used to measure the current flowing in the circuit
3- A resistance:
It has the symbol of the zigzag line. Resistance could be any device that consumes the power in the circuit.
4- A switch:
This has the symbol of the line at the bottom of the circuit. In its current status, the switch is off which means that no current is flowing in the circuit. If we connect the open terminal of the switch with the circuit, the switch is said to be on and current would flow in the circuit.
Hope this helps :)
<span>PE = mass * height * g = 87.60 J
Frictional force = m * g * sin theta * uk = 4.7 kg * 9.81 m/sec^2 * sin 36.87 * 0.3 = 8.299 N
Work done by friction = force * distance = 41.50 J
Remaining energy to be converted to KE = 87.60 J - 41.50 J = 41.10 J</span>hope it helps
Answer:
The moment of inertia of a skater is :
Explanation:
we can use parallel theorem to find the moment of inertia of a skater.
- Arm extended cylinder mass:
- Radius:
- Length:
- and